Day046 - 128. Longest Consecutive Sequence

업데이트:

128. Longest Consecutive Sequence

Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.

You must write an algorithm that runs in O(n) time.

Example 1:

Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.

Example 2:

Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9

Constraints:

  • 0 <= nums.length <= 105
  • -109 <= nums[i] <= 109


내 풀이

class Solution:
    def longestConsecutive(self, nums: List[int]) -> int:
     
        nums_set = set(nums)

        # The Longest Consecutive Elements Sequence
        lces = 0

        for i in nums:
            if i-1 not in nums_set:

                add_num = 1
                temp_lces = 1

                while (i+add_num) in nums_set:
                    temp_lces += 1
                    add_num += 1

                lces = max(lces, temp_lces)

        return lces

# Time Complexity : \(O(N)\)


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