Day046 - 128. Longest Consecutive Sequence
업데이트:
128. Longest Consecutive Sequence
Given an unsorted array of integers nums
, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n)
time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
Constraints:
0 <= nums.length <= 105
-109 <= nums[i] <= 109
내 풀이
class Solution:
def longestConsecutive(self, nums: List[int]) -> int:
nums_set = set(nums)
# The Longest Consecutive Elements Sequence
lces = 0
for i in nums:
if i-1 not in nums_set:
add_num = 1
temp_lces = 1
while (i+add_num) in nums_set:
temp_lces += 1
add_num += 1
lces = max(lces, temp_lces)
return lces
# Time Complexity : \(O(N)\)
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